And go

has to have a ... or a _ over the 9 to be valid

but yes, 9/9 = 1

redx be trollin

And they hating

not if we are in base 15.
:P

It's discuss, not 'and go'

Newb

Not this fluff again

FU Red

uuuhmmmmmm

fluff if I know.

[quote poster=Trife; 31622; 570535]It's discuss, not 'and go'

Newb] [/quotequote poster=Red X; 31622; 570512]And they hating [/quote]

yes

no

1 is 1, nothing else is.

no matter how many 9's you add it will never reach one, but it will be VERY VERY close.

people come up with stupid arguments for it that there is an infinite amount of 9's, but that is bullfluff as nothing is infinite.
max you can have is 10^183 9's which is a lot but not infinite and not 1

There are many things that are infinite. There are an infinite number of fractions of 1 inch between two points on a ruler.

@brainwave: if that's true then you can't have a decimal representation of 1/3rd either..
0.33333333... is always less than 1/3 by your logic. However this contradicts several facets of number theory and real analysis. By definition, any repeating decimal with a pattern can be expressed as a rational number A/B where A and B are integers (they can be the same integer, B cannot be 0 :P)
So X = 0.33333....
10X = 3.333333333...
this 9X = 3
and X = 3/9 = 1/3.

Now lets try that with 0.999999....
X = 0.9999....
10X = 9.999999999....
9X = 9
X = 1.
See?
You can't tell me that my logic works for all repeating decimals except for 9... the way I'm doing multiplication and subtraction is well defined for *all* real numbers, and division (the way I'm doing it) for all real numbers except 0:P

Even if you don't agree with me, 0.9999999.... must be expressible as A/B. So if it isn't 1, what is it?

also if you don't believe me: here are a whole ton of proofs and discussion about it:
http://en.wikipedia.org/wiki/0.999...

You are funny sir.

10^183 + 1 is larger than 10^183, so the latter can't possibly the max number of 9's you can have.

GET OUTSIDE AND PLAY!!!!

PAINT MY FENCE!